SOLUTION: A Merchant mixes tea that sells for $7.20/kg and tea that sells for $9.20/kg to make 100 kg of tea that he sells for $8.80/kg. How many kilograms of each type of tea did he mix?

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Question 236182: A Merchant mixes tea that sells for $7.20/kg and tea that sells for $9.20/kg to make 100 kg of tea that he sells for $8.80/kg. How many kilograms of each type of tea did he mix?
Also to solve it, it has to be either the substitution or elimination method.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
X+Y=100 OR X=100-Y
7.20X+9.20Y=8.80*100 NOW REPLACE X IN THISD EQUATION BY (100-Y) & SOLVE FOR X.
7.20(100-Y)+9.20Y=880
720-7.20Y+9.20Y=880
2Y=880-720
2Y=160
Y=160/2
Y=80 POUNDS OF THE $9.20 TEA IS USED.
X+80=100
X=100-80
X=20 POUNDS OF THW $7.20 TEA IS USED.
PROOF:
7.20*20+9.20*80=880
144+736=880
880=880