SOLUTION: log7^4x + log7^(x+1) = ½log7^64

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Question 2361: log7^4x + log7^(x+1) = ½log7^64
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
are you sure you mean ^ ie 7 to the power 4x or rather "log of 4x, to the base 7"?
Jon