SOLUTION: Express as a single logarithm.
1) 1/2log(base m)4 + log(base m)(1/5) - 2log(base m)√6
2) logx + 3logy - 1/2[logz]
Find the exact value using properties of exponents and
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-> SOLUTION: Express as a single logarithm.
1) 1/2log(base m)4 + log(base m)(1/5) - 2log(base m)√6
2) logx + 3logy - 1/2[logz]
Find the exact value using properties of exponents and
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Question 236054: Express as a single logarithm.
1) 1/2log(base m)4 + log(base m)(1/5) - 2log(base m)√6
2) logx + 3logy - 1/2[logz]
Find the exact value using properties of exponents and logarithms. No decimal answers.
3) log(base 2)40 - log(base 2)(15/4) + log(base 2)12 Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! Express as a single logarithm.
1) 1/2log(base m)4 + log(base m)(1/5) - 2log(base m)√6
log(base m)4^(1/2) + log(base m)(1/5) - log(base m)√6^2
log(base m)2 + log(base m)(1/5) - log(base m)6
log(base m)2(1/5) - log(base m)6
log(base m)(2/5) - log(base m)6
log(base m)(2/5)/6
log(base m)(2/6*5)
log(base m)(1/3*5)
log(base m)(1/15)
.
2) logx + 3logy - 1/2[logz]
logx + logy^3 - logz^1/2
log (xy^3) - logz^1/2
log (xy^3/z^1/2)
log (xy^3/√z)
log (xy^3√z/z)
Find the exact value using properties of exponents and logarithms. No decimal answers.
3) log(base 2)40 - log(base 2)(15/4) + log(base 2)12
log(base 2)40/(15/4) + log(base 2)12
log(base 2)(160/15) + log(base 2)12
log(base 2)(32/3) + log(base 2)12
log(base 2)(32/3)*12
log(base 2)32*4
log(base 2)128
log(base 2)2^7
7
