SOLUTION: The product of two positive consecutive integers is 41 more than their sum

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: The product of two positive consecutive integers is 41 more than their sum      Log On


   

Question 236044: The product of two positive consecutive integers is 41 more than their sum
Found 2 solutions by nyc_function, Alan3354:
Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
This question is incomplete. Where's the rest of the question?

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The product of two positive consecutive integers is 41 more than their sum
-------
x*(x+1) = x + (x+1) + 41
x%5E2+%2B+x+=+2x+%2B+42
x%5E2+-+x+-+42+=+0
(x-7)*(x+6) = 0
x = 7 --> 7 and 8
------
x = -6 --> -6 and -5