SOLUTION: four consecutive odd integers such the smallest is 25 less than the sum of the two latgest integers

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Question 235913: four consecutive odd integers such the smallest is 25 less than the sum of the two latgest integers
Answer by Stitch(470) About Me  (Show Source):
You can put this solution on YOUR website!
Equation 1: X+%2B+%28X%2B2%29+%2B+%28X%2B4%29+%2B+%28X%2B6%29 The 4 integers in term of the smallest one. We increase each number by two because you only want the odd numbers.
Equation 2:X+=+%28X%2B4%29+%2B+%28X%2B6%29+-+25 combine like terms
X+=+2X+-+15 Subtract X from both sides
0+=+X+-+15 Add 15 to both sides
15+=+X
Now plug 15 in for X into equation 1 to get the 4 numbers
Equation 1: X+%2B+%28X%2B2%29+%2B+%28X%2B4%29+%2B+%28X%2B6%29
15+%2B+%2815%2B2%29+%2B+%2815%2B4%29+%2B+%2815%2B6%29 Simplify
15+%2B+17+%2B+19+%2B+21
Check your answers
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19 + 21 = 40
40 - 25 = 15