SOLUTION: I'm being to decide whether the givin point lies on the graph of the line. The equation is this: 2y-4x=8,(-2, 8).
This is over some work that I missed in class and I am not unde
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-> SOLUTION: I'm being to decide whether the givin point lies on the graph of the line. The equation is this: 2y-4x=8,(-2, 8).
This is over some work that I missed in class and I am not unde
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Question 235632: I'm being to decide whether the givin point lies on the graph of the line. The equation is this: 2y-4x=8,(-2, 8).
This is over some work that I missed in class and I am not understanding it. Could you please help? Answer by rfer(16322) (Show Source):
You can put this solution on YOUR website! Go ahead and solve the equation creating an input/output table, graph those points, draw a line the covers your points the see if this point falls on your line,
Give it a try.
Bob
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