Question 235533: how do you multiply (4^-2 * 2^-3)
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Answer by MathPro(14)   (Show Source):
You can put this solution on YOUR website! Good Afternoon,
Your problem is:
how do you multiply (4^-2 * 2^-3)?
First let’s rewrite this and use 4 = 2*2 = 2^2 to get
(2*2)^-2 * 2^-3 = (2^2)^-2*2^-3
Another rule is (x^a)^b = x ^(a*b). Lets use this rule to rewrite the equation as:
2^(-2*2) * 2^-3 =
2 ^-4 *2^-3
Use the product rule : x^a*x^b = x^(a + b) to get
2^( -4 +-3) = 2 ^ -7
Check the answer:
4^-2*2^-3 = (1/16)*(1/8)=1/128
2^-7 = 1/128
Both agree so the answer is correct.
Good Luck!
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