Question 235467: How many liters of a 40% solution and an 16% solution must be mixed to obtain 20 liters of a 22% solution? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How many liters of a 40% solution and 16% solution must be mixed to obtain 20 liters of a 22% solution?
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Equation:
0.40x + 0.16(20-x) = 0.22(20)
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Multiply thru by 100 to get:
40x + 16*20 - 16x = 22*20
24x = 6*20
x = 5 liters (amount of 40% solution needed in the mixture)
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20-x = 20-5 = 15 liters (amount of 16% solution needed in the mixture)
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Cheers,
Stan H.
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