SOLUTION: please prove: {{{(sin(x)+sin(3x))/(cos(x)+cos(3x))=tan(2x)}}}

Algebra ->  Trigonometry-basics -> SOLUTION: please prove: {{{(sin(x)+sin(3x))/(cos(x)+cos(3x))=tan(2x)}}}      Log On


   



Question 235431: please prove: %28sin%28x%29%2Bsin%283x%29%29%2F%28cos%28x%29%2Bcos%283x%29%29=tan%282x%29
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
%28sin%28x%29%2Bsin%283x%29%29%2F%28cos%28x%29%2Bcos%283x%29%29=tan%282x%29

Work with only the left side:

Write x as 2x-x and 3x as 2x%2Bx

%28sin%282x-x%29%2Bsin%282x%2Bx%29%29%2F%28cos%282x-x%29%2Bcos%282x%2Bx%29%29=tan%282x%29

Use the identities
sin%28alpha-beta%29=+sin%28alpha%29cos%28beta%29-cos%28alpha%29sin%28beta%29
and 
sin%28alpha%2Bbeta%29=+sin%28alpha%29cos%28beta%29%2Bcos%28alpha%29sin%28beta%29
to rewrite the numerator and
use the identities 
cos%28alpha-beta%29=+cos%28alpha%29cos%28beta%29%2Bsin%28alpha%29sin%28beta%29
and
cos%28alpha%2Bbeta%29=+cos%28alpha%29cos%28beta%29-sin%28alpha%29sin%28beta%29

to rewrite the denominator 



Remove the parentheses



Cancel:






The two terms on top are like terms, and
the two terms on the bottom are also like terms

%0D%0A%282sin%282x%29cos%28x%29+%29%2F%0D%0A%282cos%282x%29cos%28x%29+%29

Cancel the 2'a and the cosines:



sin%282x%29%2Fcos%282x%29

Use identity sin%28phi%29%2Fcos%28phi%29=tan%28phi%29

tan%282x%29

Edwin