SOLUTION: A jar of dimes and quarters contains $10.95. There were 93 coins in the jar. How many dimes were in the jar?

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Question 235415: A jar of dimes and quarters contains $10.95. There were 93 coins in the jar. How many dimes were in the jar?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
q+d=93 q=93-d
.25q+.10d=10.95
.25(93-d)+.10d=10.95
23.25-.25d+.10d=10.95
-.15d=10.95-23.25
-.15d=-12.30
d=-12.30/-.15
d=82 number of dimes.
q+82=93
q=93-82
q=11 number of quarters.
Proof:
.25*11+.10*82=10.95
2.75+8.20=10.95
10.95=10.95