Question 235413: Two groups of ten sprinters run 100 meters. The times required by sprinters in the first group are as follows:
12.0 12.9 10.1 14.6 11.9 11.3 13.0 12.9 13.3 10.0
The times required by sprinters in the second group are as follows:
11.6 12.5 12.3 10.2 16.3 17.0 19.1 18.7 12.3 16.4
Assuming that = 0.02, test the hypothesis that the means of the two populations are equal.
· State the null and alternate hypotheses
· Calculate the mean and standard deviation for each group
· Calculate the value of the test statistic.
· Determine the critical value(s).
· State your decision: Should the null hypothesis be rejected?
Thank you so very much for helping with this problem. I really do appreciate all of your hard work.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Two groups of ten sprinters run 100 meters. The times required by sprinters in the first group are as follows:
12.0 12.9 10.1 14.6 11.9 11.3 13.0 12.9 13.3 10.0
The times required by sprinters in the second group are as follows:
11.6 12.5 12.3 10.2 16.3 17.0 19.1 18.7 12.3 16.4
Assuming that alpha = 0.02, test the hypothesis that the means of the two populations are equal.
· State the null and alternate hypotheses
Ho: u(1)-u(2) = 0
Ha: u(1)-u(2) is not 0
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· Calculate the mean and standard deviation for each group
Grp 1: mean = 12.2 ; std = 1.445
Grp 2: mean = 14.64 ; std = 3.202
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· Calculate the value of the test statistic.
I ran a 2-Sample Ttest and got the following:
ts = t = -2.1965
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· Determine the critical value(s).
invT(0.01, with df=12.517) = -2.3266
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· State your decision: Should the null hypothesis be rejected?
Since the test statistic is not in the reject interval, do not
reject Ho.
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Cheers,
Stan H.
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