SOLUTION: trains a andb are traveling in the same direction on parallel tracks. train a is traveling at 80 miles per hour and train b is traveling at 100 miles per hour. train a passes a st
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-> SOLUTION: trains a andb are traveling in the same direction on parallel tracks. train a is traveling at 80 miles per hour and train b is traveling at 100 miles per hour. train a passes a st
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Question 235211: trains a andb are traveling in the same direction on parallel tracks. train a is traveling at 80 miles per hour and train b is traveling at 100 miles per hour. train a passes a station at 3:10 pm. If train B passes the same station at 3:22 pm at what time will train b catch up to a. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! trains a and b are traveling in the same direction on parallel tracks. train a is traveling at 80 miles per hour and train b is traveling at 100 miles per hour. train a passes a station at 3:10 pm. If train B passes the same station at 3:22 pm at what time will train b catch up to a.
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from the given information, we know that train B is 12 min (.2 hr) behind
train A, when train A passes the station
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The distance between the trains at this time: .2 * 100 = 20 mi
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Let t = time required for train B to catch train a
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write a distance equation: Dist = speed * time
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Train b travel dist = Train a travel dist + 20 mi
100t = 80t + 20
100t - 80t = 20
20t =
t = 1 hr
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3:10 + 1:00 = 4:10 pm, B catches A
:
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Check solution by finding the distances (train b travels 20 mi more than train b)
100 * 1 = 100 mi
80 * 1 = 80 mi
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difference = 20 mi
