SOLUTION: the manager of a coffe shop has one type of coffee that sells for $6 per pound and another type that sells for $14 per pound. the manager wishes to mix 100 puonds of the $14 coffee

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: the manager of a coffe shop has one type of coffee that sells for $6 per pound and another type that sells for $14 per pound. the manager wishes to mix 100 puonds of the $14 coffee      Log On


   



Question 235209: the manager of a coffe shop has one type of coffee that sells for $6 per pound and another type that sells for $14 per pound. the manager wishes to mix 100 puonds of the $14 coffee to get a mixture that will sell for $8 per pound. how many pounds of the $6 coffee should he use?.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = lbs of $6 cofee needed
100 = lbs of $14 coffee needed
%286x+%2B+100%2A14%29+%2F+%28x+%2B+100%29+=+8
6x+%2B+1400+=+8%2A%28x+%2B+100%29
6x+%2B+1400+=+8x+%2B+800
2x+=+600
x+=+300
300 pounds of the $6 coffee are needed
check:
%286x+%2B+100%2A14%29+%2F+%28x+%2B+100%29+=+8
%286%2A300+%2B+100%2A14%29+%2F+%28300+%2B+100%29+=+8
%281800+%2B+1400%29%2F400+=+8
3200%2F400+=+8
8+=+8
OK