SOLUTION: The half-life of a certain radioactive substance is 15 years.
Suppose that at time t = 0, there are 29 g of the substance.
Then after t years, the number of grams of the substa
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-> SOLUTION: The half-life of a certain radioactive substance is 15 years.
Suppose that at time t = 0, there are 29 g of the substance.
Then after t years, the number of grams of the substa
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Question 235145: The half-life of a certain radioactive substance is 15 years.
Suppose that at time t = 0, there are 29 g of the substance.
Then after t years, the number of grams of the substance remaining will be
How many grams of the substance will remain after 45 years?
You can put this solution on YOUR website! The half life formula
A = Ao(2^(-t/h))
Where
A = resulting amt after t yrs
Ao = initial amt
h = half-life of substance
:
The half-life of a certain radioactive substance is 15 years.
Suppose that at time t = 0, there are 29 g of the substance.
Then after t years, the number of grams of the substance remaining will be:
A = 29(2^(-t/15))
:
How many grams of the substance will remain after 45 years?
A = 29(2^(-45/15))
A = 29(2^-3)
A = 29*.125
A = 3.625 grams
