SOLUTION: The product of two consecutive integers is 8 more than twice their sum. Find the integers.

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Question 235069: The product of two consecutive integers is 8 more than twice their sum. Find the integers.
Answer by Stitch(470) About Me  (Show Source):
You can put this solution on YOUR website!
Given:
Equation 1: B+=+A+%2B+1 This is because they are consecutive integers
Equation 2: A%2AB+=+8+%2B+2%2A%28A%2BB%29
Solution:
Start by plugging A + 1 in equation 2 for B
A%2AB+=+8+%2B+2%2A%28A%2BB%29
A%2A%28A%2B1%29+=+8+%2B+2%2A%28A%2B%28A%2B1%29%29 Then simplify the equation
A%5E2+%2B+A+=+8+%2B+2%2A%282A+%2B+1%29 Simplify again
A%5E2+%2B+A+=+8+%2B+4A+%2B+2%29 Combine like terms
A%5E2+%2B+A+=+10+%2B+4A%29 Subtract 4A from both sides
A%5E2+-+3A+=+10%29 Subtract 10 from both sides
A%5E2+-+3A+-10+=+0%29 This equation can be foiled
A%5E2+-+3A+-10+=+%28A%2B2%29%2A%28A-5%29+=+0%29
That gives you 2 possible answers for A.
A + 2 = 0 or rewritten as A = -2
& A - 5 = 0 or rewritten as A = 5
Since 5 is the only positive number it is most likely the answer you would want in this case. But you should always check both.
Now plug 5 in equation 1 for A
B+=+A+%2B+1
B+=+5+%2B+1
B+=+6
Now check the answers
A%2AB+=+8+%2B+2%2A%28A%2BB%29
5%2A6+=+8+%2B+2%2A%285%2B6%29
30+=+8+%2B+2%2A%2811%29
30+=+8+%2B+22
30+=+30