Question 234929: Jeb has 25 coins. They are all quarters and nickels. He has a total of $2.85. How many quarters and nickels does he have? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Jeb has 25 coins. They are all quarters and nickels. He has a total of $2.85. How many quarters and nickels does he have?
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n + q = 25 (25 coins)
5n + 25q = 285 (value of coins)
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2 eqns in 2 unknowns
q = 25-n (from eqn 1)
Sub for q into eqn 2
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5n + 25(25-n) = 285
5n + 625 - 25n = 285
-20n = -340
n = 17 nickels
q = 8
