SOLUTION: A migrating elephant herd started moving at a rate of 6 mph. One elephant stood still and was left behind. Then this stray elephant sensed danger and began running at a rate of 1

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: A migrating elephant herd started moving at a rate of 6 mph. One elephant stood still and was left behind. Then this stray elephant sensed danger and began running at a rate of 1      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 234741: A migrating elephant herd started moving at a rate of 6 mph. One elephant stood still and was left behind. Then this stray elephant sensed danger and began running at a rate of 10 mph to reach the herd. The stray elephant caught up in 5 min. How long (in hours) did the stray run to catch up? how far did it run? Find the distance that the herd traveled while the stray ran to catch up. Then write an expression for the total distance the herd traveled. Let x represent the distance (in miles) that the herd traveled while the stray elephant stood still.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A migrating elephant herd started moving at a rate of 6 mph.
One elephant stood still and was left behind.
Then this stray elephant sensed danger and began running at a rate of 10 mph to reach the herd.
The stray elephant caught up in 5 min. How long (in hours) did the stray run to catch up?
5%2F60 = .0833 hrs
:
how far did it run?
.0833 * 10 = .833 miles
:
Find the distance that the herd traveled while the stray ran to catch up.
.0833 * 6 = .5 miles
:
Then write an expression for the total distance the herd traveled.
Let x represent the distance (in miles) that the herd traveled while the stray elephant stood still.
d = x + .5 mi
:
Dist herd traveled = distance stray traveled (when he caught up)
x + .5 = .833 mi
x = .833 - .5
x = .333 mi while the stray stood still