Question 234711: Joann is five years older than her sister Teresa, Joann's age is one less than twice Teresa's. Find the ages of both girls.
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Joann is five years older than her sister Teresa, Joann's age is one less than twice Teresa's. Find the ages of both girls.
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Equations:
j = t + 5
j = 2t - 1
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Substitute and solve for "t":
t+5 = 2t-1
t = 6 (Teresa's age)
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Since j= t+5, j=11 (Joann's age)
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Cheers,
Stan H.
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