SOLUTION: Find two consecutive numbers such that 3/4 of the first number is 5 more than 1/2 the second number

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Question 234619: Find two consecutive numbers such that 3/4 of the first number is 5 more than 1/2 the second number
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Two consecutive numbers: x, (x+1)
:
Find two consecutive numbers such that 3/4 of the first number is 5 more than 1/2 the second number.
3%2F4x = 1%2F2(x+1) + 5
;
Get rid of the denominators, multiply all terms by 4, results
3x = 2(x+1) + 4(5)
:
3x = 2x + 2 + 20
:
3x - 2x = 22
:
x = 22 & 23 are the numbers
;
:
Check solution in the statement:
"two consecutive numbers such that 3/4 of the first number is 5 more than 1/2 the second number."
3%2F422 = 1%2F2(23) + 5
16.5 = 11.5 + 5