SOLUTION: A club consists of 10 men and 12 women. What is the probability of selecting two men and two women to attend the conference?

Algebra ->  Probability-and-statistics -> SOLUTION: A club consists of 10 men and 12 women. What is the probability of selecting two men and two women to attend the conference?      Log On


   



Question 234477: A club consists of 10 men and 12 women. What is the probability of selecting two men and two women to attend the conference?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A club consists of 10 men and 12 women. What is the probability of selecting two men and two women to attend the conference?
-----------
# of ways to select 2 men: 10C2 = 45
# of ways to select 2 women: 12C2: 66
-----------------------------
# of ways to pick 4 of any gender: 22C4 = 7315
============
P(2 mena and 2 women) = [45*66]/7315 = 0.4060
===================
Cheers,
Stan H.