Question 234465: Two times the least of three consecutive odd integers exceeds three times the greatest by 15. What are the integers? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! Let x, x+2 & x+4 be the 3 odd integers.
2x>3(x+4)+15
2x>3x+12+15
2x-3x>27
-x>27
x<-27 (Note: when dividing by a negative value the > sign changes to a < sign).
Proof:
Let x=-26
2*-26>3(-26+4)+15
-52>3*-22+15
-52>-66+15
-52>-51