SOLUTION: find the maximum value: f(x)= -10/3(x+5)^2-5

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: find the maximum value: f(x)= -10/3(x+5)^2-5      Log On


   

Question 234417: find the maximum value:
f(x)= -10/3(x+5)^2-5
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
find the maximum value:
f(x)= -10/3(x+5)^2-5
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The vertex is at (-5,-5) so I guess that y-value
is the maximum value.
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Cheers,
Stan H.