SOLUTION: Translate the problem into a pair of linear equations in two variables.
A sum of money amounting to $3.80 consist of dimes and quarters. If there are 20 coins in all, how many a
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-> SOLUTION: Translate the problem into a pair of linear equations in two variables.
A sum of money amounting to $3.80 consist of dimes and quarters. If there are 20 coins in all, how many a
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Question 234380: Translate the problem into a pair of linear equations in two variables.
A sum of money amounting to $3.80 consist of dimes and quarters. If there are 20 coins in all, how many are quarters? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! Q+D=20 OR Q=20-D
.25Q+.10D=3.80
.25(20-D)+.10D=3.80
5-.25D+.10D=3.80
-15D=3.80-5
.15D=1.20
D=1.20/.15
D=8 NUMBER OF DIMES.
Q=20-8=12 NUMBER OF QUARTERS.
PROOF:
.25*12+8*.10=3.80
3+.80=3.80
3.80=3.80
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