SOLUTION: #4 EllEN WISHES TO MIX CANDY WORTH $1.92 PER POUND WITH CANDY WORTH $3.11 PER POUND TO FORM 36 POUNDS OF A MIXTURE WORTH $2.48 PER POUND. HOW MANY POUNDS OF THE MORE EXPENSIVE CAND
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-> SOLUTION: #4 EllEN WISHES TO MIX CANDY WORTH $1.92 PER POUND WITH CANDY WORTH $3.11 PER POUND TO FORM 36 POUNDS OF A MIXTURE WORTH $2.48 PER POUND. HOW MANY POUNDS OF THE MORE EXPENSIVE CAND
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Question 234235: #4 EllEN WISHES TO MIX CANDY WORTH $1.92 PER POUND WITH CANDY WORTH $3.11 PER POUND TO FORM 36 POUNDS OF A MIXTURE WORTH $2.48 PER POUND. HOW MANY POUNDS OF THE MORE EXPENSIVE CANDY SHOULD SHE USE? Answer by solver91311(24713) (Show Source):
Is there some reason you feel the need to SHOUT? Typing in ALL CAPS is the electronic equivalent of shouting, and is therefore both annoying and rude. Please stop.
Let represent the number of pounds of $3.11 per-pound candy. Since there are to be a total of 36 pounds in the final mixture, the number of pounds of $1.92 per-pound candy must be: .
If there are pounds of candy that cost $3.11, then the total cost of that part of the mixture must be . Likewise the total cost of the less expensive part of the mixture must be . And finally, the total cost of the overall mixture must be $2.48 times 36. The sum of the costs of the two kinds of candy must be the total cost of the mixture, so:
