SOLUTION: Fraction: 2/-2^-3 is supposed to be equal to 16.
But I don't get it.
Can someone explain the process for my understanding? I don't know
how to deal with negative exponents espe
Algebra ->
Exponents-negative-and-fractional
-> SOLUTION: Fraction: 2/-2^-3 is supposed to be equal to 16.
But I don't get it.
Can someone explain the process for my understanding? I don't know
how to deal with negative exponents espe
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Question 234136: Fraction: 2/-2^-3 is supposed to be equal to 16.
But I don't get it.
Can someone explain the process for my understanding? I don't know
how to deal with negative exponents especially when it's in a fraction. Answer by nyc_function(2741) (Show Source):
You can put this solution on YOUR website! 2/-2^-3 is supposed to be equal to 16.
Use the rule that says: a^(-1) = 1/(a)^(+1)
Actually, the answer is not 16 but -16.
2/-2^-3 becomes 2/(-2)^(-3) = 2/(1/-8)
For 2/(1/-8), we multiply the top and bottom by -8.
So, 2/(1/-8) becomes 2(-8)/1 = -16/1 = -16
The correct answer is -16.
