Question 234116: one number is four more than twice a second number. their difference is eleven. find the two numbers
Answer by nyc_function(2741)   (Show Source):
You can put this solution on YOUR website! Let x = first number
Let y = second number
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x = 2y + 4
Their difference = 11 can be expressed as x - y = 11
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We have two equations in 2 unknowns.
x = 2y + 4...Equation A
x - y = 11...Equation B
Replace x in Equation B with its value given in Equation A and solve for y.
2y + 4 - y = 11
y + 4 = 11
y = 11 - 4
y = 7....This is one of the numbers.
To find x, we plug y = 7 into either Equation A or B (your choice) and solve for x.
I will use x - y = 11.
Let y = 7
x - 7 = 11
x = 11 + 7
x = 18
The numbers are 7 and 18.
If you think about it, 18 is 4 more than twice 7, right?
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