SOLUTION: If the first and third of three consecutive odd integers are added, the result is 57 less than five times the second integer. Find the third integer.
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Question 233925: If the first and third of three consecutive odd integers are added, the result is 57 less than five times the second integer. Find the third integer. Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! Let x, x+2 & x+4 be the 3 odd integers.
x+x+4=5(x+2)-57
2x+4=5x+10-57
2x-5x=10-57-4
-3x=-51
x=-51/-3
x=17 ans for the first odd integer.
17+2 is the second osdd integer.
17+4=21 is the third odd integer.
Proof:
17+21=5*19-57
38=95-57
38=38
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