Question 23376: I have two questions I just don't get them.
Solve the system of linear equations by graphing: x+2y=5
x-y=2
that is the first one
the second one is: 4x-y=6
3x+y=1
these are very hard for me please help Answer by venugopalramana(3286) (Show Source):
You can put this solution on YOUR website! SECOND PROBLEM IS SHOWN BELOW.
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SOLVE BY GRAPHING MEANS DRAW THE GRAPHS AND FIND THE 2 GRAPHS OF 2 EQUATIONS CUT EACH OTHER .THAT IS THE SOLUTION.LET ME SHOW YOU THE SECOND PROBLEM.
4X-Y=6..OR...4X-6=Y.....
3X+Y=1...OR....Y=1-3X.........
LET X=...........................0......1......2........3.........4......ETC..
Y=4X-6..IN FIRST EQN........-6......-2.....2........6.........10.......ETC
Y=1-3X..IN SECOND EQN.......1.......-2.....-5.......-8........-11......ETC
THE GRAPHS WILL LOOK LIKE THIS
WE FIND THAT THE TWO GRAPHS ARE CUTTING AT X=1 AND Y=-2.HENCE THAT IS THE SOLUTION..YOU CAN CHECK BACK
EQN.I.....4X-Y=4*1-(-2)=4+ 2 = 6 ..OK
EQN.II.....3X+Y=3*1+(-2)=3-2=1........OK.
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Solve the system of linear equations by graphing: x+2y=5..
OR 2Y=5-X..OR Y=(5-X)/2
x-y=2...
OR Y=X-2
that is the first one
the second one is: 4x-y=6
3x+y=1
SOLVE BY GRAPHING MEANS DRAW THE GRAPHS AND FIND THE 2 GRAPHS OF 2 EQUATIONS CUT EACH OTHER .THAT IS THE SOLUTION.LET ME SHOW YOU THE FIRST PROBLEM. THEN YOU CAN DO SECOND PROBLEM THE SAME WAY
LET X=.........................0......1......2........3.........4......5....ETC.
Y=(5-X)/2..IN FIRST EQN........5/2....2......3/2......1.........1/2....0...ETC
Y=(X-2).....IN SECOND EQN.......-2....-1......0........1.........2......3...ETC
THE GRAPHS WILL LOOK LIKE THIS
WE FIND THAT THE TWO GRAPHS ARE CUTTING AT X=3 AND Y=1.HENCE THAT IS THE SOLUTION..YOU CAN CHECK BACK
EQN.I.....X+2Y=3+2*1=3+2=5..OK
EQN.II.....X-Y=3-1=2........OK.
