Question 23373: 6x-(3-2x)>3x+2 how do you do this??????
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! 6x-(3-2x)>3x+2
Distribute the -:
6x - 3 + 2x > 3x +2
8x - 3 > 3x +2
Subtract 3x from each side:
8x - 3 -3x > 3x +2 -3x
5x -3 > 2
Add +3 to each side:
5x-3 + 3 > 2+ 3
5x > 5
Divide both sides by 5:
x>1
Graph on a numberline by going 1 unit to the right, and shade everything to the right of 1, with an arrow on the right end of the numberline, since x>1 means x is any number LARGER than 1, and since it goes forever in the right direction. To indicate that the endpoint at x=1 is NOT included, make an open circle at the point x=1. In higher math, we use an open parentheses on the point x=1, opening to the right.
R^2 at SCC
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