SOLUTION: I am thinking of three consecutive negative numbers. If I multiply the first with the second and than subtract three times the third, the result is 57. what are the numbers? Hin
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Question 233380: I am thinking of three consecutive negative numbers. If I multiply the first with the second and than subtract three times the third, the result is 57. what are the numbers? Hint: Property of consecutive integers.)))
Please help with this one! I submitted it earlier for help but forgot to add the negative part to the problem. Its given me plenty of trouble! Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! LET X, X+1 & X+2 BE THE 3 INTEGERS.
X(X+1)-3(X+2)=57
X^2+X-3X-6=57
X^2-2X-6-57=0
X^2-2X-63=0
(X-9)(X+7)=0
X+7=0
X=-7 ANS.
-7+1=-6 ANS.
-7+2=-5 ANS.
PROOF:
-7*-6-3(-5)=57
42+15=57
57=57
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