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Question 233360: (((I am thinking of three consecutive numbers. If I multiply the first with the second and then subtract three times the third, the result is 57. What are the numbers? Hint: Property of consecutive integers.)))
Please help me I am lost on this one. tried it over and over and I can't come up with a solution. or even an equation.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! I am thinking of three consecutive numbers. If I multiply the first with the second and then subtract three times the third, the result is 57. What are the numbers?
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1st: x-1
2nd: x
3rd: x+1
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Equation:
(x-1)x-3(x+1)= 57
x^2-x-3x-3 = 57
x^2-4x-60 = 0
x^2-10x+6x-60 = 0
x(x-10)+6(x-10) = 0
(x-10)(x+6) = 0
x = 10 or x = -6
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If x = 10 the numbers are 9,10,11
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If x = -6 the numbers are -7,-6,-5
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Cheers,
Stan H.
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