Question 233126: Find 2 consecutive #'s such that when you square the smaller number,the result is 8 less than the product of the 2 #'s? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find 2 consecutive #'s such that when you square the smaller number,the result is 8 less than the product of the 2 #'s?
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smaller: x
larger: x+1
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Equation:
x^2 = x(x+1)-8
x^2 = x^2+x-8
x = 8 (smaller number)
x+1 = 9 (larger number)
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Cheers,
Stan H.
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