SOLUTION: The number of candy in the jar is a 3 digit number.
The sum of the digits is odd.
When you divide the number by 2 you have a remainer of 1.
When you divide the number by 10 you
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-> SOLUTION: The number of candy in the jar is a 3 digit number.
The sum of the digits is odd.
When you divide the number by 2 you have a remainer of 1.
When you divide the number by 10 you
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Question 232959: The number of candy in the jar is a 3 digit number.
The sum of the digits is odd.
When you divide the number by 2 you have a remainer of 1.
When you divide the number by 10 you have a remainder of 3.
The sum of the units digits and the tens digit is 1 less than the hundredths digit.
The units digit is half the sum of the hundredths digit and the tens digit. Answer by solver91311(24713) (Show Source):
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The fact that the sum of the digits is odd and that when you divide the number by 2 the remainder is 1 are both fascinating facts but are not particularly useful in solving the problem.
The fact integer division by 10 has a remainder of 3 guarantees that the last or units digit is 3. Let represent the tens digit, and let represent the hundreds digit.
The sum of the units digit and the tens digit, is (meaning equals) one less than the hundreds digit. , so:
Add 1 to both sides:
The units digit is half the sum of the hundreds (you said hundredths digit, but there cannot be a hundreths digit because dividing the 3 digit number by 10 resulted in an integer, not a decimal fraction.) digit and the tens digit.
Substitute the expression developed for :
Solve for and then use that value to solve for Then you can reassemble the number by placing the digits in the proper order.
