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| Question 232816:    Find four consecutive even integers so that the sum of the first three is 2 more than twice the fourth
 
 Answer by mando271(42)
      (Show Source): 
You can put this solution on YOUR website! let the 1st integer be x. since they have to be consecutive, the 2nd will be x+2, the 3rd x+4 and the 4th x+6.
 so,
 x+x+2+x+4 = 2(x+6)+2, now solve for x
 3x+6 = 2x+12+2
 x=8
 so substituting 8 for x. the integers are:
 8, 10, 12, 14
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