SOLUTION: A bus service runs between two cities. Going one way, the average speed of the bus is 66 mph, and going the other way, it is 3 mph slower, so the ride takes 20 minutes longer. What
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Question 232736: A bus service runs between two cities. Going one way, the average speed of the bus is 66 mph, and going the other way, it is 3 mph slower, so the ride takes 20 minutes longer. What is the distance between the two cities?
I have come up with this but I am not positive if its right:
Distance 66(x)and 63(x+20)
Rate 66 and 63
Time is x and x+20? Found 2 solutions by rfer, josmiceli:Answer by rfer(16322) (Show Source):
You can put this solution on YOUR website! 66x=63(x+1/3)
66x=63x+21
3x=21
x=7 miles
Don't mix minutes and hours
otherwise your setup looks good.
You can put this solution on YOUR website! Right idea, but the units for time all need to be the same. Call the trip back
since hrs
(1)
(2)
This is 2 equations and 2 unknowns, so it should be solvable is the same in both, so set (1) = (2) hrs
and
(1) mi
The distance between the cities is 462 mi
check:
(2)
OK