Question 232225: find the vertex and graph of y= -x2 + 6x - 5.5
Found 2 solutions by stanbon, checkley77:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! find the vertex and graph of y= -x^2 + 6x - 5.5
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You have a quadratic with a=-1, b = 6, c = -5.5
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Vertex occurs when x = -b/2a = -6/(-2) = 3
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The corresponding y-value is:
f(3) = -(3)^2 + 6*3 - 5.5 = -14.5 +18 = 3.5
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So, vertex at (3,3.5)
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y-intercept at f(0) = -5.5
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Parabola opens downward because a < 0.
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Cheers,
Stan H.
Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! y= -x2 + 6x - 5.5
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, -x^2 +6x -5.5).
y=-3^3+6*3-5,5
y=-9+18-5,5
y=18-14.5
y=3.5
Vertex=(3,3.5)
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