Question 232155: solve for x:
1/x-4 - 3x/x^2-16=2/X+4
SIMPLY THIS COMPLEX FRACTION:
8M^2/3M-6 / 40M/M-2
I got m/45 is that right?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! solve for x:
1/(x-4) - 3x/(x^2-16) = 2/(X+4)
Multiply thru by x^2-16 to get:
x+4 - 3x = 2(x-4)
4-2x = 2x-8
Add 2x to both sides ; Add 8 to both sides
12 = 4x
x = 3
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SIMPLY THIS COMPLEX FRACTION:
8M^2/(3M-6) / 40M/(M-2)
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Invert the denominator and multiply
(8M^2)/(3(M-2)) times (M-2)/40M
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Cancel all factors you can find that are common to a numerator and a denominator
such as 8,M,(M-2)
(M)/3) times (1/5)
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Cheers,
Stan H.
= M/15
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