SOLUTION: Please help me solve this equation: {{{ 16 ^ (2 - x) + 16^( x) = 40 }}}. Thanks~

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Question 23195: Please help me solve this equation: +16+%5E+%282+-+x%29+%2B+16%5E%28+x%29+=+40++.
Thanks~
Answer by dkspoet(13) About Me  (Show Source):
You can put this solution on YOUR website!
16^(2-x)+16^x = 40
16^2/16^x+16^x = 40
256+16^2x = 40(16^x)
16^2x-40(16^x)+256 = 0
16^2x-8(16^x)-32(16^x)+256 = 0
16^x(16^x-8)-32(16^x-8) = 0
(16^x-32)(16^x-8) = 0
16^x = 32 or 16^x = 8
x = 5/4 or x = 3/4