Question 231918:  Robert invests $8000 in a bank. Part is invested at 7% simple interest and part at 9% simple interest. In one year Robert earns $660 in interest. How much did he invest at each amount? 
 Answer by checkley77(12844)      (Show Source): 
You can  put this solution on YOUR website! .09X+.07(8,000-X)=660 
.09X+560-.07X=660 
.02X=660-560 
.02X=100 
X=100/.02 
X=5,000 AMOUNT INVESTED @ 9%. 
8,000-5,000=3,000 AMOUNT INVESTED @ 7%. 
PROOF: 
.09*5,000+.07*3,000=660 
450+210=660 
660=660 
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