SOLUTION: use the given conditions to write an equation for the line in point-slop form, slope intercept form, and standard form. Passing though(1,-2)and parallel to the line whose equati

Algebra ->  Linear-equations -> SOLUTION: use the given conditions to write an equation for the line in point-slop form, slope intercept form, and standard form. Passing though(1,-2)and parallel to the line whose equati      Log On


   

Question 231631: use the given conditions to write an equation for the line in point-slop form, slope intercept form, and standard form.
Passing though(1,-2)and parallel to the line whose equation is 2x-4y=9
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Use the given conditions to write an equation for the line in point-slope form,
slope intercept form, and standard form.
Passing though(1,-2)and parallel to the line whose equation is 2x-4y=9
:
Find the slope of the given equation by finding the slope/intercept form
2x - 4y = 9
-4y = -2x + 9
We need y to be positive, multiply equation by -1
4y = 2x - 9
Divide equation by 4
y = 2%2F4x - 9%2F4
y = .5x - 2.25
:
slope (m) = .5
:
Parallel lines have the same slope; use the point/slope form to find the equation: y - y1 = m(x-x1)
In this equation: m=.5; x1=1; y1=-2
y - (-2) = .5(x - 1); the point slope form
y + 2 = .5x - .5
y = .5x - .5 - 2
y = .5x - 2.5; the slope intercept form
:
Find the standard form
y = .5x - 2.5
-.5x + y = -2.5
Multiply eq by -2
x - 2y = 5; the standard form of the line parallel to 2x - 4y = 9