SOLUTION: two trains that are 495 mi apart travel towards each other. They pass each other 5 hrs later. If one trains is traveling half as fast as the other, what are their speed?
5x+5y=4
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: two trains that are 495 mi apart travel towards each other. They pass each other 5 hrs later. If one trains is traveling half as fast as the other, what are their speed?
5x+5y=4
Log On
Question 231608: two trains that are 495 mi apart travel towards each other. They pass each other 5 hrs later. If one trains is traveling half as fast as the other, what are their speed?
5x+5y=495
x=1/2-y
5(1/2-y)+5y=495
then lost
Thanks
Erika Answer by rfer(16322) (Show Source):
You can put this solution on YOUR website! You have a two step problem.
r=D/t
r=495/5
r=99 mph total speed coming together
------------------------------------
2x+x=99
3x=99
x=33 mph
2x=66 mph
Does that help?
Bob