Question 23158: I need help on figuring out the sides for triangle PQR. Coordinates given: P=(-2,6); Q=(-2,0); R=(5,0).
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! Normally you would need to use the distance formula to find the three distances between these points. However, comparing P(-2,6) and Q(-2,0), you can see that P is directly above Q, at a distance of 6 units. Comparing Q(-2,0) and R(5,0), you can see that these are both on the x axis at a distance of 7 units. Moreover, you can see that line PQ is perpendicular to line QR and the x-axis, so this is a right triangle. You can use the Theorem of Pythagoras to find PR =  .
R^2 at SCC
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