SOLUTION: a two-digit number has a ten's digit that is two less the unit's digit. The number formed by reversing the digits exceeds the orginal number by three times the unit's digit. What
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Question 231541: a two-digit number has a ten's digit that is two less the unit's digit. The number formed by reversing the digits exceeds the orginal number by three times the unit's digit. What is the number. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Let 10x + y = the two digit number
:
"has a ten's digit that is two less the unit's digit."
x = y - 2
:
"The number formed by reversing the digits exceeds the original number by three times the unit's digit."
10y + x = (10x + y) + 3y
10y + x = 10x = 4y
10y - 4y = 10x - x
6y = 9x
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What is the number.
Replace x with (y-2) in the above equation
6y = 9(y-2)
6y = 9y - 18
+18 = 9y - 6y
18 = 3y
y =
y = 6
then
x = 6 - 2
x = 4
:
46 = the two digit number
:
:
Check solution in the statement:a two-dig
" number formed by reversing the digits exceeds the original number by three times the unit's digit."
64 = 46 + 3(6)
64 = 46 + 18
