SOLUTION: I am completely lost in trying to solve the following equations. I respectfully ask for your help and assistance. Thank you. Robert 1. Use the addition method to solve

Algebra ->  Equations -> SOLUTION: I am completely lost in trying to solve the following equations. I respectfully ask for your help and assistance. Thank you. Robert 1. Use the addition method to solve       Log On


   



Question 23138: I am completely lost in trying to solve the following equations. I respectfully ask for your help and assistance. Thank you.
Robert

1.
Use the addition method to solve the following system of equations:
(1/3)X + Y = 3 AND (1/2)X - (1/4)Y = 1

2.
Use the substitution method to solve the following system of equations:
2x+5y = 1 and -x+6y = 8

Answer by stanbon!(97) About Me  (Show Source):
You can put this solution on YOUR website!
Prob. #1
First, get rid of the fractions:
Multiply 1st equation thru by 3 to get:
X + 3Y=9
Multiply 2nd equation thru by 4 to get:
2x- Y = 4
Now multiply this last equation thru by 3 so we can get rid of the Y's.
6X -3Y = 12
This is now the equations you are working with:
1st: X +3Y= 9
2nd: 6X-3Y= 12
Now add the two equations to get:
7x = 21
x = 3
Put this value into one of the early equations to solve for "Y".
3 + 3Y = 9
3Y = 6
Y = 2
Solution: X= 3 and Y= 2
Check that answer in the original equations.
2nd Problem:
2x+5y=1
x=6y-8
Substitute this value of "x" into the 1st equation to get:
2(6y-8)+5y = 1
12y-16+5y = 1
17y = 17
y = 1
Substitute that value into one of the original equations to get:
x=(6(1))-8
x= 6-8=2
Solution:
x = 2 and y = 1
Check that answer in the othe original equation.
Cheers,
Stan H.