SOLUTION: shiela invests part of part of$6000 at 6% interest and the other part at 11% interest. Her total annual income from these investments is $460. How much is investes at each rate?

Algebra ->  Finance -> SOLUTION: shiela invests part of part of$6000 at 6% interest and the other part at 11% interest. Her total annual income from these investments is $460. How much is investes at each rate?      Log On


   

Question 231290: shiela invests part of part of$6000 at 6% interest and the other part at 11% interest. Her total annual income from these investments is $460. How much is investes at each rate?
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
.06x+.11(6000-x)=460
.06x+660-.11x=460
-.05x=-200
x=$4000 at 6%
$2000 at 11%