SOLUTION: A bag contains pennies and nickels only. If there are 182 coins in the bag and they add up to $3.90, how many of each type of coin do you have?

Click here to see ALL problems on Word Problems With Coins

Question 231251: A bag contains pennies and nickels only. If there are 182 coins in the bag and they add up to $3.90, how many of each type of coin do you have?
Found 2 solutions by stanbon, texttutoring:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
A bag contains pennies and nickels only. If there are 182 coins in the bag and they add up to $3.90, how many of each type of coin do you have?
-----------------------------------
Quantity Equation: p + n = 182 coins
Value Equation:::: p +5n = 390 cents
------------------------------------------------
Subtract the Quantity Eq. from the Value Eq to get
4n = 208
n = 52 (number of nickels)
---
Substitute into p+n=182 to solve for "p":
p + 52 = 182
p = 130 (# of pennies)
==============================
Cheers,
Stan H.

Answer by texttutoring(324) (Show Source):
You can put this solution on YOUR website!
We need to have two equations, and two variables.
Let p=number of pennies.
Let n=number of nickels
Eqn 1: p+n=182
Eqn 2: 0.01*p+0.05*n=3.90
Isolate Eqn 1 for n:
n=182-p
Substitute this into Eqn 2:
0.01*p +0.05(182-p)=3.90
0.01*p +9.1-0.05p=3.90
Combine like terms and rearrange to get:
9.1-3.90=0.05p-0.01p
5.2=0.04p
Divide both sides by 0.04:
p=130
You can then find the number of nickels from Eqn 1:
182-130=n
n=52
There are 130 pennies and 52 nickels.