SOLUTION: Translate the problem into a pair of linear equations in two vaiables
The perimeter of a rectangle is 72 m. If the width were doubled and the length were increased by 9 m, then th
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The perimeter of a rectangle is 72 m. If the width were doubled and the length were increased by 9 m, then th
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Question 231238: Translate the problem into a pair of linear equations in two vaiables
The perimeter of a rectangle is 72 m. If the width were doubled and the length were increased by 9 m, then the perimeter would be 114 m. What are the dimensions?
You can put this solution on YOUR website! 2L+2W=72
2(L+9)+2(2W)=114
2L+18+4W=114
2L+4W=114-18
2L+4W=96
2L+2W=72 SUBTRACT THIS EQUATION
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2W=24
W=24/2
W=12 ANS. FOR THE ORIGINAL WIDTH.
2L+2*12=72
2L+24=72
2L=72-24
2L=48
L=48/2
L=24 ANS. FOR THE ORIGINAL LENGTH.
PROOF:
2*24+2*12=72
48+24=72
72=72
2(24+9)+2(2*12)=114
2*33+2*24=114
66+48=114
114=114
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