SOLUTION: Find 2 consecutive integers such that twice the smaller exceeds the larger by 8

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Question 231185: Find 2 consecutive integers such that twice the smaller exceeds the larger by 8
Answer by user_dude2008(1862) About Me  (Show Source):
You can put this solution on YOUR website!
2x=(x+1)+8
2x=x+9
2x-x=9
x=9 <------- First #
x+2=10 <------- second #