SOLUTION: One positive integer is 5 greater than the other. The sum of the square of the two integers is 37. Find the two numbers. my work: 5x^2+x^2=37 6x^2=37 6x^

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Question 230918: One positive integer is 5 greater than the other. The sum of the square of the two integers is 37. Find the two numbers.


my work: 5x^2+x^2=37
6x^2=37
6x^2/6=37/6
x^2=37/6
(x^2)^1/2=(37/6)^1/2
x=2.48
I am not getting the correct answer using this formula.
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Let x= first number
x+5= second number

Your equation will be

x%5E2%2B%28x%2B5%29%5E2=37
x%5E2+%2Bx%5E2%2B10x%2B25=37

2x%5E2%2B10x-12=0
2%28x%5E2%2B5x-6%29=0
2%28x%2B6%29%28x-1%29=0
x=-6 or x=1

There are two solutions:
x=-6 and x+5=-1

Also,
x=1 and x+5=6

Dr. Robert J. Rapalje