SOLUTION: An express and local train leave Grayslake at 3pm and head for chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: An express and local train leave Grayslake at 3pm and head for chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the      Log On


   

Question 230904: An express and local train leave Grayslake at 3pm and head for chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train.
I have this set up I think ok but thats about as far as I get
rate time distance
Local x t 50
Express x(2) t -1 50
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
D=RT
50=R(T-1)
50=R/2*T
R(T-1)=RT/2
RT-R=RT/2
2RT-2R=RT
2RT-RT=2R
RT=2R
T=2R/R
T=2 HOURS FOR THE SLOW TRAIN.
2-1=1 HOUR FOR THE FAST TRAIN.
50=R(2-1)
50=R FOR THE FASTER TRAIN.
PROOF:
50=50(2-1)
50-50
50=50/2*2
50=25*2
50=50